Help with ano equation for a counter balance weight?

[stephen4785]

I need to engineer a counter balance for a piece of equipment but I can't remember how to calculate the amount of force. If I have 100 lbs and move it out 4 feet what does that equal at the pivot?

[Strychnine]

Not enough info.

You have 100 lbs at 4 ft in one direction... In the other direction what's the distance from the fulcrum to your counterweight?

[Nash B.]

Force x radius, so if one side is 100 pounds x 4 feet, the other side needs to be 400 ft-lbs

[GhostTX]

Not enough info.

You have 100 lbs at 4 ft in one direction... In the other direction what's the distance from the fulcrum to your counterweight?

This.

X lb -Y'---^--4'-100 lb

Edit: Nash is correct, too. Torque = F X L.

[Strychnine]

I'm spending my Friday night working and I felt generous.

[yellowstang]

Just keep adding weight until it balances

[stephen4785]

I dopnt know how much the mulcher arm assembly weighs. It can boom out 25ft and the mulcher head weighs 1200lbs. it already has a 1 1/4 thick plate on the side thats 32"x17. I was thinking of making an arm that has a 100gallon tank on it that can be lowered via a small winch or a hydraulic cylinder. I was even thinking about making the arm able to telescope out so you can fine tune it in the cab. That way you could lower it from 1 degree to 45 degress, telescope it out, and watch a bubble level in the cab to get it level. the problem is that the mulching arm can articulate(its basically an excavator style arm) so it'll never be a set amount for a counter weight.
This is the machine

[stephen4785]

We added the hyrail gear on the front and rear and to get the rear tires on the track I cut the inside of the wheels out and re-welded them so the tires moved in 5inches which narrowed the wheel base. We also filled the tires with water to add weight. Id really like to figure out a system where the counter weight automatically booms out and compensates for the muclher head but i think it would be a little complicated.