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  • Math help

    dy/dx = [cos(x-y) / sin(x)sin(y)] - 1

    Solve for y.

    Not liking this class already.
    class joke
    {
    private:
    char Forrest, Jenny, Momma, LtDan;
    double Peas, Carrots;
    string MommaAlwaysSaid(const bool AddAnyTime = True)
    };

  • #2
    4?

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    • #3
      I was thinking 3.25
      Karussell White - 2010 Genesis Coupe R-Spec 6MT 2.0T -

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      • #4
        Use sum/difference formula: cos(x-y) = cos(x)cos(y) + sin(x)sin(y)

        then it becomes: [[cos(x)cos(y) + sin(x)sin(y)] / sin(x)sin(y)] -1

        which simplifies to: dy/dx = cos(x)cos(y)/sin(x)sin(y)

        That should get you started.
        Last edited by BERNIE MOSFET; 01-25-2011, 03:48 PM.
        Men have become the tools of their tools.
        -Henry David Thoreau

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        • #5
          Hold on I'm asking my abacus.
          Originally posted by talisman
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          Originally posted by AdamLX
          If there was, I wouldn't pick it because it would probably just keep leaving the game and then coming back like nothing happened.
          Originally posted by Broncojohnny
          Because fuck you, that's why
          Originally posted by 80coupe
          nice dick, Idrivea4banger
          Originally posted by Rick Modena
          ......and idrivea4banger is a real person.
          Originally posted by Jester
          Man ive always wanted to smoke a bowl with you. Just seem like a cool cat.

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          • #6
            I tried to cheat using google, no luck. Heh.

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            • #7
              Originally posted by MOSFET View Post
              Use sum/difference formula: cos(x-y) = cos(x)cos(y) + sin(x)sin(y)

              then it becomes: [[cos(x)cos(y) + sin(x)sin(y)] / sin(x)sin(y)] -1

              which simplifies to: dx/dy = cos(x)cos(y)/sin(x)sin(y)

              That should get you started.
              English motherfucker! Do you speak it?

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              • #8
                Originally posted by mosfet View Post
                use sum/difference formula: Cos(x-y) = cos(x)cos(y) + sin(x)sin(y)

                then it becomes: [[cos(x)cos(y) + sin(x)sin(y)] / sin(x)sin(y)] -1

                which simplifies to: Dy/dx = cos(x)cos(y)/sin(x)sin(y)

                that should get you started.

                witch!!!!

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                • #9
                  I think it's C

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                  • #10
                    I'm rusty but I got arccos( (sin x) / C). Haven't taken calculus in over 6 years though
                    Originally posted by Broncojohnny
                    HOORAY ME and FUCK YOU!

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                    • #11
                      Differential equations? Man that was so long ago i'd have to break out my book if I cared to solve it. Wait till that class gets hard.

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                      • #12
                        Originally posted by Mysticcobrakilla View Post
                        English motherfucker! Do you speak it?
                        Originally posted by roliath View Post
                        witch!!!!



                        Holy shit, that made me laugh!
                        Men have become the tools of their tools.
                        -Henry David Thoreau

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                        • #13
                          Tony=(fat girls+no self esteem)+1

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                          • #14
                            It's been a while since I've taken any math classes but that looks like one of those formulas where "y" is going to equal 1 or -1, because all you're basically gonna be doing is zero'ing out each part of the equation in different ways. I need to go back to school. Although, this shows just how much we don't use this shit in real life.
                            "Any dog under 50lbs is a cat and cats are pointless." - Ron Swanson

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                            • #15
                              Originally posted by poopnut2 View Post
                              It's been a while since I've taken any math classes but that looks like one of those formulas where "y" is going to equal 1 or -1, because all you're basically gonna be doing is zero'ing out each part of the equation in different ways.
                              No.
                              Originally posted by Broncojohnny
                              HOORAY ME and FUCK YOU!

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